Nondirectional hypothesis: Answer the questions below, following the Submission Requirements as specified at the end of the assessment. To calculate t when needed, refer to the T-Table for Assessment 3 document linked in the Resources under the Required Resources heading.
|Question 1||Independent Variables (IVs) and Dependent Variables (DVs)|
|Question 3||Errors and Significance: Type 1 and Type 2 Error|
|Question 4||Errors and Significance: Type 1 and Type 2 Error|
|Question 5||Hypothesis Testing and the z Score|
|Question 6||Standard Error of the Mean|
|Question 7||Central Limit Theorem|
|Question 8||Normal Deviate Z Test|
|Question 9||One Sample t Test|
|Question 10||SPSS: One Sample t Test|
|Question 11||Confidence Intervals|
A researcher randomly assigns a group of adults to one of two diet plans (Diet Plan A or Diet Plan B). The researcher then measures the amount of weight loss each participant experiences in a two-week period. What are the IV and the DV in this study?
A researcher is studying whether the amount of weight loss differs in participants who follow Diet Plan A versus those who follow Diet Plan B. Write the following:
In the general population, it is an established fact that men weigh, on average, more than women. For your study, you randomly sample 100 men and 100 women, recording each participant’s weight, and you find no significant difference in weight based on gender. What type of error is this (Type 1 or Type 2), given that a difference really does exist in the population? Explain your answer.
In general, men and women do not differ on IQ. However, as part of your study, you found that women scored significantly higher than men on IQ. Given that you found a difference in your study where none exists in the general population, identify the error (Type 1 or Type 2) and explain your answer.
Joan is 72 inches tall. The average (mean) height for adult women is 65 inches, and the standard deviation is 3.5 inches. Complete the following:
College students in a large psychology class take a final exam. The mean exam score is 85, and the standard deviation is 5. Using the formula for σM , identify the standard error of the mean (σM) under the following conditions:
As part of a large research study, you administer a new test to 20,000 adults. Before you record or analyze the data, can you assume that the sampling distribution of the mean for this test will be normally distributed? Why or why not?
The average (mean) height for adult women is 65 inches, and the standard deviation is 3.5 inches. Given the women you know, you think this number is low, so you record the heights of 25 of your female friends. The average height of your 25 friends is 66.84 inches. If your friends are just a representative sample of adult females, what is the probability that your friends are so tall?
The average (mean) height for adult women is 65 inches, and the standard deviation is 3.5 inches. Given the women you know, you think this number is low, so you record the heights of 9 of your female friends. Below are their heights in inches:
65, 67, 62, 67, 59, 68, 69, 70, 67.
Complete the following:
Remember, you must show all your work to receive credit.
Complete the following steps:
Based on the SPSS output from Question 10 above, and the test value (population mean) of 65, calculate the 95 percent confidence interval.
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