Given a one independent variable linear equation that states cost in

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1) Given a one independent variable linear equation that states cost in $K, and given the following information, calculate the coefficient of variation and determine its meaning.
[removed][removed]

 
 
 

[removed]If we used this equation, we could typically expect to be off by ± 10.77%.

[removed]If we used this equation, we could typically expect to be off by ± 29.31%.

[removed]If we used this equation, we could typically expect to be off by ± 9.32%.

[removed]If we used this equation, we could typically expect to be off by ± 33.85%.

2) You are estimating the cost ($K) of optical sensors based on the resolution of the sensor (i.e. how small of an object it can detect). Using the preliminary calculations from a data set of 8 sensors, determine the equation of the line. (Round your intermediate calculations to 3 decimal places)
∑Y = 2515 ∑X = 30 ∑XY = 6857.5 ∑X2 = 161
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[removed]Cost = – 53.067 + 115.374 (Resolution)

[removed]Cost = 513.376 + (- 53.067) (Resolution)

[removed]Cost = 115.374 + (-53.067) (Resolution)

[removed]Cost = – 53.067 + 513.376 (Resolution)

3) You are trying to determine the statistical significance of an equation. Given the following information, test the slope of the equation at the 95% level of confidence. Select the correct answer out of each pair of choices.

Cost = – 76.25 + 114.82 (Range) n = 9 Sb1 = 17.669
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[removed]The tp is 1.895

[removed]The tp is 2.365

[removed]The tc is 4.315

[removed]The tc is 6.498

[removed]We would reject the null hypothesis

[removed]We would fail to reject the null hypothesis

[removed]We would consider using the equation

[removed]We would not use the equation

4) You have calculated the following power model and associated unit space values: You would select the:
[removed][removed]

 
 
 

[removed]Power equation because it has a higher standard error than the linear model.

[removed]Power equation because it has a lower standard error than the linear model.

[removed]Linear equation because it has a higher standard error than the power model.

[removed]Linear equation because it has a lower standard error than the power model.

5) A coworker is considering the use of a log linear (power) model using weight to estimate the cost of a utility vehicle. They have performed the following calculations in log space using natural logarithms. Select the corresponding unit space form of this power model equation.

Log Space b1 = 1.268074 b0 = 0.062153
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[removed]Cost = 1.268074 + 0.062153 (Weight)

[removed]Cost = 0.062153 + 1.268074 (Weight)

[removed]Cost = 1.064125 (Weight) 1.268074

[removed]Cost = 0.062153 (Weight) 1.268074

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